Sumedh

Is *(*(p+i)+j) is equivalent to p[i][j]? Is num[i] == i[num] == *(num + i) == *(i + num)?




Yes

*( *(p + i) + j) == p[ i ][ j ].

So is num[i] == i[num] == *(num + i) == *( i + num)




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